(3x+5)(x^2+4x-5)=0

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Solution for (3x+5)(x^2+4x-5)=0 equation:


Simplifying
(3x + 5)(x2 + 4x + -5) = 0

Reorder the terms:
(5 + 3x)(x2 + 4x + -5) = 0

Reorder the terms:
(5 + 3x)(-5 + 4x + x2) = 0

Multiply (5 + 3x) * (-5 + 4x + x2)
(5(-5 + 4x + x2) + 3x * (-5 + 4x + x2)) = 0
((-5 * 5 + 4x * 5 + x2 * 5) + 3x * (-5 + 4x + x2)) = 0
((-25 + 20x + 5x2) + 3x * (-5 + 4x + x2)) = 0
(-25 + 20x + 5x2 + (-5 * 3x + 4x * 3x + x2 * 3x)) = 0
(-25 + 20x + 5x2 + (-15x + 12x2 + 3x3)) = 0

Reorder the terms:
(-25 + 20x + -15x + 5x2 + 12x2 + 3x3) = 0

Combine like terms: 20x + -15x = 5x
(-25 + 5x + 5x2 + 12x2 + 3x3) = 0

Combine like terms: 5x2 + 12x2 = 17x2
(-25 + 5x + 17x2 + 3x3) = 0

Solving
-25 + 5x + 17x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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